-4(x-2)+5x=4(x+2)-5

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Solution for -4(x-2)+5x=4(x+2)-5 equation: 



-4(x-2)+5x=4(x+2)-5

We move all terms to the left:

-4(x-2)+5x-(4(x+2)-5)=0

We add all the numbers together, and all the variables

5x-4(x-2)-(4(x+2)-5)=0

We multiply parentheses

5x-4x-(4(x+2)-5)+8=0



We calculate terms in parentheses: -(4(x+2)-5), so:

4(x+2)-5

We multiply parentheses

4x+8-5

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We add all the numbers together, and all the variables

x-(4x+3)+8=0

We get rid of parentheses

x-4x-3+8=0

We add all the numbers together, and all the variables

-3x+5=0

We move all terms containing x to the left, all other terms to the right

-3x=-5

x=-5/-3

x=1+2/3

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