-4(x-2)+6x-15-x(4-3)=14-3(x+2)+7x+4

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Solution for -4(x-2)+6x-15-x(4-3)=14-3(x+2)+7x+4 equation: 



-4(x-2)+6x-15-x(4-3)=14-3(x+2)+7x+4

We move all terms to the left:

-4(x-2)+6x-15-x(4-3)-(14-3(x+2)+7x+4)=0

We add all the numbers together, and all the variables

-4(x-2)+6x-x1-(14-3(x+2)+7x+4)-15=0

We add all the numbers together, and all the variables

5x-4(x-2)-(14-3(x+2)+7x+4)-15=0

We multiply parentheses

5x-4x-(14-3(x+2)+7x+4)+8-15=0



We calculate terms in parentheses: -(14-3(x+2)+7x+4), so:

14-3(x+2)+7x+4

determiningTheFunctionDomain
-3(x+2)+7x+14+4

We add all the numbers together, and all the variables

7x-3(x+2)+18

We multiply parentheses

7x-3x-6+18

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

x-(4x+12)-7=0

We get rid of parentheses

x-4x-12-7=0

We add all the numbers together, and all the variables

-3x-19=0

We move all terms containing x to the left, all other terms to the right

-3x=19

x=19/-3

x=-6+1/3

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