-4(x-2)+6x-15-x(4-3)=14-3(x+2)+7x+4

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Solution for -4(x-2)+6x-15-x(4-3)=14-3(x+2)+7x+4 equation:



-4(x-2)+6x-15-x(4-3)=14-3(x+2)+7x+4
We move all terms to the left:
-4(x-2)+6x-15-x(4-3)-(14-3(x+2)+7x+4)=0
We add all the numbers together, and all the variables
-4(x-2)+6x-x1-(14-3(x+2)+7x+4)-15=0
We add all the numbers together, and all the variables
5x-4(x-2)-(14-3(x+2)+7x+4)-15=0
We multiply parentheses
5x-4x-(14-3(x+2)+7x+4)+8-15=0
We calculate terms in parentheses: -(14-3(x+2)+7x+4), so:
14-3(x+2)+7x+4
determiningTheFunctionDomain -3(x+2)+7x+14+4
We add all the numbers together, and all the variables
7x-3(x+2)+18
We multiply parentheses
7x-3x-6+18
We add all the numbers together, and all the variables
4x+12
Back to the equation:
-(4x+12)
We add all the numbers together, and all the variables
x-(4x+12)-7=0
We get rid of parentheses
x-4x-12-7=0
We add all the numbers together, and all the variables
-3x-19=0
We move all terms containing x to the left, all other terms to the right
-3x=19
x=19/-3
x=-6+1/3

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