-4(x-2)+6x-15x(4-3)=14-3(x+2)+7x-4

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Solution for -4(x-2)+6x-15x(4-3)=14-3(x+2)+7x-4 equation: 



-4(x-2)+6x-15x(4-3)=14-3(x+2)+7x-4

We move all terms to the left:

-4(x-2)+6x-15x(4-3)-(14-3(x+2)+7x-4)=0

We add all the numbers together, and all the variables

-4(x-2)+6x-15x1-(14-3(x+2)+7x-4)=0

We add all the numbers together, and all the variables

-9x-4(x-2)-(14-3(x+2)+7x-4)=0

We multiply parentheses

-9x-4x-(14-3(x+2)+7x-4)+8=0



We calculate terms in parentheses: -(14-3(x+2)+7x-4), so:

14-3(x+2)+7x-4

determiningTheFunctionDomain
-3(x+2)+7x+14-4

We add all the numbers together, and all the variables

7x-3(x+2)+10

We multiply parentheses

7x-3x-6+10

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

-13x-(4x+4)+8=0

We get rid of parentheses

-13x-4x-4+8=0

We add all the numbers together, and all the variables

-17x+4=0

We move all terms containing x to the left, all other terms to the right

-17x=-4

x=-4/-17

x=4/17

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