-4(x-2)=-(-2+x)x=

Solution for -4(x-2)=-(-2+x)x= equation:

-4(x-2)=-(-2+x)x=

We move all terms to the left:

-4(x-2)-(-(-2+x)x)=0

We add all the numbers together, and all the variables

-4(x-2)-(-(x-2)x)=0

We multiply parentheses

-4x-(-(x-2)x)+8=0


We calculate terms in parentheses: -(-(x-2)x), so:

-(x-2)x

We multiply parentheses

-x^2+2x

We add all the numbers together, and all the variables

-1x^2+2x

Back to the equation:

-(-1x^2+2x)


We get rid of parentheses

1x^2-2x-4x+8=0

We add all the numbers together, and all the variables

x^2-6x+8=0

a = 1; b = -6; c = +8;
Δ = b2-4ac
Δ = -62-4·1·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*1}=\frac{4}{2}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*1}=\frac{8}{2}
=4
$