-4(x-2)=2(-2x+3)-5

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Solution for -4(x-2)=2(-2x+3)-5 equation: 



-4(x-2)=2(-2x+3)-5

We move all terms to the left:

-4(x-2)-(2(-2x+3)-5)=0

We multiply parentheses

-4x-(2(-2x+3)-5)+8=0



We calculate terms in parentheses: -(2(-2x+3)-5), so:

2(-2x+3)-5

We multiply parentheses

-4x+6-5

We add all the numbers together, and all the variables

-4x+1

Back to the equation:

-(-4x+1)



We get rid of parentheses

-4x+4x-1+8=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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