-4(x-3)+12=20

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Solution for -4(x-3)+12=20 equation: 



-4(x-3)+12=20

We move all terms to the left:

-4(x-3)+12-(20)=0

We add all the numbers together, and all the variables

-4(x-3)-8=0

We multiply parentheses

-4x+12-8=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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