-4(x-3)-(2x-4)+3=2(2x-3)-2

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Solution for -4(x-3)-(2x-4)+3=2(2x-3)-2 equation: 



-4(x-3)-(2x-4)+3=2(2x-3)-2

We move all terms to the left:

-4(x-3)-(2x-4)+3-(2(2x-3)-2)=0

We multiply parentheses

-4x-(2x-4)-(2(2x-3)-2)+12+3=0

We get rid of parentheses

-4x-2x-(2(2x-3)-2)+4+12+3=0



We calculate terms in parentheses: -(2(2x-3)-2), so:

2(2x-3)-2

We multiply parentheses

4x-6-2

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

-6x-(4x-8)+19=0

We get rid of parentheses

-6x-4x+8+19=0

We add all the numbers together, and all the variables

-10x+27=0

We move all terms containing x to the left, all other terms to the right

-10x=-27

x=-27/-10

x=2+7/10

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