-4(x2+x+2)=0

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Solution for -4(x2+x+2)=0 equation: 



-4(x2+x+2)=0

We add all the numbers together, and all the variables

-4(+x^2+x+2)=0

We multiply parentheses

-4x^2-4x-8=0

a = -4; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·(-4)·(-8)
Δ = -112
Delta is less than zero, so there is no solution for the equation

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