-4(x4x)=2(2-x)+10

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Solution for -4(x4x)=2(2-x)+10 equation: 



-4(x4x)=2(2-x)+10

We move all terms to the left:

-4(x4x)-(2(2-x)+10)=0

We add all the numbers together, and all the variables

-4x4x-(2(-1x+2)+10)=0



We calculate terms in parentheses: -(2(-1x+2)+10), so:

2(-1x+2)+10

We multiply parentheses

-2x+4+10

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We get rid of parentheses

-4x4x+2x-14=0

We add all the numbers together, and all the variables

2x-4x4x-14=0

We move all terms containing x to the left, all other terms to the right

2x-4x4x=14

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