-4(y+1)+6=2(y+2)-8

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Solution for -4(y+1)+6=2(y+2)-8 equation:



-4(y+1)+6=2(y+2)-8
We move all terms to the left:
-4(y+1)+6-(2(y+2)-8)=0
We multiply parentheses
-4y-(2(y+2)-8)-4+6=0
We calculate terms in parentheses: -(2(y+2)-8), so:
2(y+2)-8
We multiply parentheses
2y+4-8
We add all the numbers together, and all the variables
2y-4
Back to the equation:
-(2y-4)
We add all the numbers together, and all the variables
-4y-(2y-4)+2=0
We get rid of parentheses
-4y-2y+4+2=0
We add all the numbers together, and all the variables
-6y+6=0
We move all terms containing y to the left, all other terms to the right
-6y=-6
y=-6/-6
y=1

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