-4(y+1)+6y=-2(y+2)-8

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Solution for -4(y+1)+6y=-2(y+2)-8 equation: 



-4(y+1)+6y=-2(y+2)-8

We move all terms to the left:

-4(y+1)+6y-(-2(y+2)-8)=0

We add all the numbers together, and all the variables

6y-4(y+1)-(-2(y+2)-8)=0

We multiply parentheses

6y-4y-(-2(y+2)-8)-4=0



We calculate terms in parentheses: -(-2(y+2)-8), so:

-2(y+2)-8

We multiply parentheses

-2y-4-8

We add all the numbers together, and all the variables

-2y-12

Back to the equation:

-(-2y-12)



We add all the numbers together, and all the variables

2y-(-2y-12)-4=0

We get rid of parentheses

2y+2y+12-4=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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