-4(y+1)+6y=2(y+)-8

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Solution for -4(y+1)+6y=2(y+)-8 equation: 



-4(y+1)+6y=2(y+)-8

We move all terms to the left:

-4(y+1)+6y-(2(y+)-8)=0

We add all the numbers together, and all the variables

-4(y+1)+6y-(2(+y)-8)=0

We add all the numbers together, and all the variables

6y-4(y+1)-(2(+y)-8)=0

We multiply parentheses

6y-4y-(2(+y)-8)-4=0



We calculate terms in parentheses: -(2(+y)-8), so:

2(+y)-8

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We add all the numbers together, and all the variables

2y-(2y-8)-4=0

We get rid of parentheses

2y-2y+8-4=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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