-4(y+1)=2y-2+2(2y+8)

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Solution for -4(y+1)=2y-2+2(2y+8) equation: 



-4(y+1)=2y-2+2(2y+8)

We move all terms to the left:

-4(y+1)-(2y-2+2(2y+8))=0

We multiply parentheses

-4y-(2y-2+2(2y+8))-4=0



We calculate terms in parentheses: -(2y-2+2(2y+8)), so:

2y-2+2(2y+8)

determiningTheFunctionDomain
2y+2(2y+8)-2

We multiply parentheses

2y+4y+16-2

We add all the numbers together, and all the variables

6y+14

Back to the equation:

-(6y+14)



We get rid of parentheses

-4y-6y-14-4=0

We add all the numbers together, and all the variables

-10y-18=0

We move all terms containing y to the left, all other terms to the right

-10y=18

y=18/-10

y=-1+4/5

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