-4(y+2)=4y-5+3(2y+3)

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Solution for -4(y+2)=4y-5+3(2y+3) equation: 



-4(y+2)=4y-5+3(2y+3)

We move all terms to the left:

-4(y+2)-(4y-5+3(2y+3))=0

We multiply parentheses

-4y-(4y-5+3(2y+3))-8=0



We calculate terms in parentheses: -(4y-5+3(2y+3)), so:

4y-5+3(2y+3)

determiningTheFunctionDomain
4y+3(2y+3)-5

We multiply parentheses

4y+6y+9-5

We add all the numbers together, and all the variables

10y+4

Back to the equation:

-(10y+4)



We get rid of parentheses

-4y-10y-4-8=0

We add all the numbers together, and all the variables

-14y-12=0

We move all terms containing y to the left, all other terms to the right

-14y=12

y=12/-14

y=-6/7

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