-4(y+2)=8y-8+2(2y+6)

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Solution for -4(y+2)=8y-8+2(2y+6) equation: 



-4(y+2)=8y-8+2(2y+6)

We move all terms to the left:

-4(y+2)-(8y-8+2(2y+6))=0

We multiply parentheses

-4y-(8y-8+2(2y+6))-8=0



We calculate terms in parentheses: -(8y-8+2(2y+6)), so:

8y-8+2(2y+6)

determiningTheFunctionDomain
8y+2(2y+6)-8

We multiply parentheses

8y+4y+12-8

We add all the numbers together, and all the variables

12y+4

Back to the equation:

-(12y+4)



We get rid of parentheses

-4y-12y-4-8=0

We add all the numbers together, and all the variables

-16y-12=0

We move all terms containing y to the left, all other terms to the right

-16y=12

y=12/-16

y=-3/4

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