-4(y+3)+2y=6(y+2)

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Solution for -4(y+3)+2y=6(y+2) equation: 



-4(y+3)+2y=6(y+2)

We move all terms to the left:

-4(y+3)+2y-(6(y+2))=0

We add all the numbers together, and all the variables

2y-4(y+3)-(6(y+2))=0

We multiply parentheses

2y-4y-(6(y+2))-12=0



We calculate terms in parentheses: -(6(y+2)), so:

6(y+2)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We add all the numbers together, and all the variables

-2y-(6y+12)-12=0

We get rid of parentheses

-2y-6y-12-12=0

We add all the numbers together, and all the variables

-8y-24=0

We move all terms containing y to the left, all other terms to the right

-8y=24

y=24/-8

y=-3

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