-4(y+3)=-2y+1)-8

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Solution for -4(y+3)=-2y+1)-8 equation: 



-4(y+3)=-2y+1)-8

We move all terms to the left:

-4(y+3)-(-2y+1)-8)=0

We add all the numbers together, and all the variables

-4(y+3)-(-2y+1)=0

We multiply parentheses

-4y-(-2y+1)-12=0

We get rid of parentheses

-4y+2y-1-12=0

We add all the numbers together, and all the variables

-2y-13=0

We move all terms containing y to the left, all other terms to the right

-2y=13

y=13/-2

y=-6+1/2

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