-4(y+3)=-3y-1

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Solution for -4(y+3)=-3y-1 equation: 



-4(y+3)=-3y-1

We move all terms to the left:

-4(y+3)-(-3y-1)=0

We multiply parentheses

-4y-(-3y-1)-12=0

We get rid of parentheses

-4y+3y+1-12=0

We add all the numbers together, and all the variables

-1y-11=0

We move all terms containing y to the left, all other terms to the right

-y=11

y=11/-1

y=-11

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