-4(y+3)=-3y-y(-7)

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Solution for -4(y+3)=-3y-y(-7) equation: 



-4(y+3)=-3y-y(-7)

We move all terms to the left:

-4(y+3)-(-3y-y(-7))=0

We multiply parentheses

-4y-(-3y-y(-7))-12=0



We calculate terms in parentheses: -(-3y-y(-7)), so:

-3y-y(-7)

We multiply parentheses

-3y+7y

We add all the numbers together, and all the variables

4y

Back to the equation:

-(4y)



We add all the numbers together, and all the variables

-8y-12=0

We move all terms containing y to the left, all other terms to the right

-8y=12

y=12/-8

y=-1+1/2

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