-4(y+3)=4y-6+2(2y+2)

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Solution for -4(y+3)=4y-6+2(2y+2) equation: 



-4(y+3)=4y-6+2(2y+2)

We move all terms to the left:

-4(y+3)-(4y-6+2(2y+2))=0

We multiply parentheses

-4y-(4y-6+2(2y+2))-12=0



We calculate terms in parentheses: -(4y-6+2(2y+2)), so:

4y-6+2(2y+2)

determiningTheFunctionDomain
4y+2(2y+2)-6

We multiply parentheses

4y+4y+4-6

We add all the numbers together, and all the variables

8y-2

Back to the equation:

-(8y-2)



We get rid of parentheses

-4y-8y+2-12=0

We add all the numbers together, and all the variables

-12y-10=0

We move all terms containing y to the left, all other terms to the right

-12y=10

y=10/-12

y=-5/6

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