-4(y-2y)+4=-4(3y-y)+1+11y

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Solution for -4(y-2y)+4=-4(3y-y)+1+11y equation: 



-4(y-2y)+4=-4(3y-y)+1+11y

We move all terms to the left:

-4(y-2y)+4-(-4(3y-y)+1+11y)=0

We add all the numbers together, and all the variables

-4(-1y)-(-4(+2y)+1+11y)+4=0

We multiply parentheses

4y-(-4(+2y)+1+11y)+4=0



We calculate terms in parentheses: -(-4(+2y)+1+11y), so:

-4(+2y)+1+11y

determiningTheFunctionDomain
-4(+2y)+11y+1

We add all the numbers together, and all the variables

11y-4(+2y)+1

We multiply parentheses

11y-8y+1

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We get rid of parentheses

4y-3y-1+4=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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