-4(y-3(y-5))=2(6-5y)

Solution for -4(y-3(y-5))=2(6-5y) equation:

-4(y-3(y-5))=2(6-5y)

We move all terms to the left:

-4(y-3(y-5))-(2(6-5y))=0

We add all the numbers together, and all the variables

-4(y-3(y-5))-(2(-5y+6))=0


We calculate terms in parentheses: -(2(-5y+6)), so:

2(-5y+6)

We multiply parentheses

-10y+12

Back to the equation:

-(-10y+12)


We get rid of parentheses

-4(y-3(y-5))+10y-12=0

We add all the numbers together, and all the variables

10y-4(y-3(y-5))-12=0

We move all terms containing y to the left, all other terms to the right

10y-4(y-3(y-5))=12