-4(y-3)+2(3y-5)=11

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Solution for -4(y-3)+2(3y-5)=11 equation: 


Simplifying
-4(y + -3) + 2(3y + -5) = 11

Reorder the terms:
-4(-3 + y) + 2(3y + -5) = 11
(-3 * -4 + y * -4) + 2(3y + -5) = 11
(12 + -4y) + 2(3y + -5) = 11

Reorder the terms:
12 + -4y + 2(-5 + 3y) = 11
12 + -4y + (-5 * 2 + 3y * 2) = 11
12 + -4y + (-10 + 6y) = 11

Reorder the terms:
12 + -10 + -4y + 6y = 11

Combine like terms: 12 + -10 = 2
2 + -4y + 6y = 11

Combine like terms: -4y + 6y = 2y
2 + 2y = 11

Solving
2 + 2y = 11

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2y = 11 + -2

Combine like terms: 2 + -2 = 0
0 + 2y = 11 + -2
2y = 11 + -2

Combine like terms: 11 + -2 = 9
2y = 9

Divide each side by '2'.
y = 4.5

Simplifying
y = 4.5

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