-4(y-4)=32(2y-1)

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Solution for -4(y-4)=32(2y-1) equation: 



-4(y-4)=32(2y-1)

We move all terms to the left:

-4(y-4)-(32(2y-1))=0

We multiply parentheses

-4y-(32(2y-1))+16=0



We calculate terms in parentheses: -(32(2y-1)), so:

32(2y-1)

We multiply parentheses

64y-32

Back to the equation:

-(64y-32)



We get rid of parentheses

-4y-64y+32+16=0

We add all the numbers together, and all the variables

-68y+48=0

We move all terms containing y to the left, all other terms to the right

-68y=-48

y=-48/-68

y=12/17

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