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-4(z+1)(-z-5)=0
We add all the numbers together, and all the variables
-4(z+1)(-1z-5)=0
We multiply parentheses ..
-4(-1z^2-5z-1z-5)=0
We multiply parentheses
4z^2+20z+4z+20=0
We add all the numbers together, and all the variables
4z^2+24z+20=0
a = 4; b = 24; c = +20;
Δ = b2-4ac
Δ = 242-4·4·20
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-16}{2*4}=\frac{-40}{8} =-5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+16}{2*4}=\frac{-8}{8} =-1 $
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