-4(z-1)-(4z-1)=-3-(7z-2)

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Solution for -4(z-1)-(4z-1)=-3-(7z-2) equation: 



-4(z-1)-(4z-1)=-3-(7z-2)

We move all terms to the left:

-4(z-1)-(4z-1)-(-3-(7z-2))=0

We multiply parentheses

-4z-(4z-1)-(-3-(7z-2))+4=0

We get rid of parentheses

-4z-4z-(-3-(7z-2))+1+4=0



We calculate terms in parentheses: -(-3-(7z-2)), so:

-3-(7z-2)

determiningTheFunctionDomain
-(7z-2)-3

We get rid of parentheses

-7z+2-3

We add all the numbers together, and all the variables

-7z-1

Back to the equation:

-(-7z-1)



We add all the numbers together, and all the variables

-8z-(-7z-1)+5=0

We get rid of parentheses

-8z+7z+1+5=0

We add all the numbers together, and all the variables

-1z+6=0

We move all terms containing z to the left, all other terms to the right

-z=-6

z=-6/-1

z=+6

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