-4(z-12)+6=48

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Solution for -4(z-12)+6=48 equation: 



-4(z-12)+6=48

We move all terms to the left:

-4(z-12)+6-(48)=0

We add all the numbers together, and all the variables

-4(z-12)-42=0

We multiply parentheses

-4z+48-42=0

We add all the numbers together, and all the variables

-4z+6=0

We move all terms containing z to the left, all other terms to the right

-4z=-6

z=-6/-4

z=1+1/2

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