-4+(1/2)x=8

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Solution for -4+(1/2)x=8 equation:



-4+(1/2)x=8
We move all terms to the left:
-4+(1/2)x-(8)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)x-4-8=0
We add all the numbers together, and all the variables
(+1/2)x-12=0
We multiply parentheses
x^2-12=0
a = 1; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·1·(-12)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*1}=\frac{0-4\sqrt{3}}{2} =-\frac{4\sqrt{3}}{2} =-2\sqrt{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*1}=\frac{0+4\sqrt{3}}{2} =\frac{4\sqrt{3}}{2} =2\sqrt{3} $

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