-4+2(3x+1)=2(2x-3)+6

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Solution for -4+2(3x+1)=2(2x-3)+6 equation:



-4+2(3x+1)=2(2x-3)+6
We move all terms to the left:
-4+2(3x+1)-(2(2x-3)+6)=0
We multiply parentheses
6x-(2(2x-3)+6)+2-4=0
We calculate terms in parentheses: -(2(2x-3)+6), so:
2(2x-3)+6
We multiply parentheses
4x-6+6
We add all the numbers together, and all the variables
4x
Back to the equation:
-(4x)
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1

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