-4+2(x-4)=1/4(8x-10)+7x

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Solution for -4+2(x-4)=1/4(8x-10)+7x equation: 



-4+2(x-4)=1/4(8x-10)+7x

We move all terms to the left:

-4+2(x-4)-(1/4(8x-10)+7x)=0



Domain of the equation: 4(8x-10)+7x)!=0

x∈R



We multiply parentheses

2x-(1/4(8x-10)+7x)-8-4=0

We multiply all the terms by the denominator


2x*4(8x-10)+7x)-(1-8*4(8x-10)+7x)-4*4(8x-10)+7x)=0

Wy multiply elements

8x^2(8+7x)-(1-32x(8+7x)-4*4(8x-10)+7x)=0



We calculate terms in parentheses: -(1-32x(8+7x)-4*4(8x-10)+7x), so:

1-32x(8+7x)-4*4(8x-10)+7x

determiningTheFunctionDomain
-32x(8+7x)-4*4(8x-10)+7x+1

We add all the numbers together, and all the variables

-32x(7x+8)-4*4(8x-10)+7x+1

We add all the numbers together, and all the variables

7x-32x(7x+8)-4*4(8x-10)+1

We multiply parentheses

-224x^2+7x-256x-4*4(8x-10)+1

Wy multiply elements

-224x^2+7x-256x-16x(8+1

We add all the numbers together, and all the variables

-224x^2-249x-16x(8+1

Back to the equation:

-(-224x^2-249x-16x(8+1)



We add all the numbers together, and all the variables

8x^2(7x+8)-(-224x^2-249x-16x9=0

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