-4+3(6x-10)=8(x+2)+10

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Solution for -4+3(6x-10)=8(x+2)+10 equation: 



-4+3(6x-10)=8(x+2)+10

We move all terms to the left:

-4+3(6x-10)-(8(x+2)+10)=0

We multiply parentheses

18x-(8(x+2)+10)-30-4=0



We calculate terms in parentheses: -(8(x+2)+10), so:

8(x+2)+10

We multiply parentheses

8x+16+10

We add all the numbers together, and all the variables

8x+26

Back to the equation:

-(8x+26)



We add all the numbers together, and all the variables

18x-(8x+26)-34=0

We get rid of parentheses

18x-8x-26-34=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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