-4+3y=3(y-3)+5

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Solution for -4+3y=3(y-3)+5 equation:


Simplifying
-4 + 3y = 3(y + -3) + 5

Reorder the terms:
-4 + 3y = 3(-3 + y) + 5
-4 + 3y = (-3 * 3 + y * 3) + 5
-4 + 3y = (-9 + 3y) + 5

Reorder the terms:
-4 + 3y = -9 + 5 + 3y

Combine like terms: -9 + 5 = -4
-4 + 3y = -4 + 3y

Add '4' to each side of the equation.
-4 + 4 + 3y = -4 + 4 + 3y

Combine like terms: -4 + 4 = 0
0 + 3y = -4 + 4 + 3y
3y = -4 + 4 + 3y

Combine like terms: -4 + 4 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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