-4+9(3k-12)=7(k-12)+12

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Solution for -4+9(3k-12)=7(k-12)+12 equation: 



-4+9(3k-12)=7(k-12)+12

We move all terms to the left:

-4+9(3k-12)-(7(k-12)+12)=0

We multiply parentheses

27k-(7(k-12)+12)-108-4=0



We calculate terms in parentheses: -(7(k-12)+12), so:

7(k-12)+12

We multiply parentheses

7k-84+12

We add all the numbers together, and all the variables

7k-72

Back to the equation:

-(7k-72)



We add all the numbers together, and all the variables

27k-(7k-72)-112=0

We get rid of parentheses

27k-7k+72-112=0

We add all the numbers together, and all the variables

20k-40=0

We move all terms containing k to the left, all other terms to the right

20k=40

k=40/20

k=2

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