-4-(3+6m)=1/2(4+2m

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Solution for -4-(3+6m)=1/2(4+2m equation: 



-4-(3+6m)=1/2(4+2m

We move all terms to the left:

-4-(3+6m)-(1/2(4+2m)=0



Domain of the equation: 2(4+2m)-4!=0

We move all terms containing m to the left, all other terms to the right

2(4+2m)!=4

m∈R



We add all the numbers together, and all the variables

-(6m+3)-(1/2(2m+4)-4=0

We get rid of parentheses

-6m-(1/2(2m+4)-4-3=0

We multiply all the terms by the denominator


-6m*2(2m+4)-4-3-(1=0

We add all the numbers together, and all the variables

-6m*2(2m+4)=0

Wy multiply elements

-12m^2(2=0

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