-4-2/3(n+9)-2=5/2(4-n)

Solution for -4-2/3(n+9)-2=5/2(4-n) equation:

-4-2/3(n+9)-2=5/2(4-n)

We move all terms to the left:

-4-2/3(n+9)-2-(5/2(4-n))=0


Domain of the equation: 3(n+9)!=0

n∈R



Domain of the equation: 2(4-n))!=0

n∈R


We add all the numbers together, and all the variables

-2/3(n+9)-(5/2(-1n+4))-4-2=0

We add all the numbers together, and all the variables

-2/3(n+9)-(5/2(-1n+4))-6=0

We calculate fractions


(-4n(-)/(3(n+9)*2(-1n+4)))+(-15nn/(3(n+9)*2(-1n+4)))-6=0


We calculate terms in parentheses: +(-4n(-)/(3(n+9)*2(-1n+4))), so:

-4n(-)/(3(n+9)*2(-1n+4))

We add all the numbers together, and all the variables

-4n0/(3(n+9)*2(-1n+4))

We multiply all the terms by the denominator


-4n0

We add all the numbers together, and all the variables

-4n

Back to the equation:

+(-4n)



We calculate terms in parentheses: +(-15nn/(3(n+9)*2(-1n+4))), so:

-15nn/(3(n+9)*2(-1n+4))

We multiply all the terms by the denominator


-15nn

Back to the equation:

+(-15nn)


We get rid of parentheses

-4n-15nn-6=0

We move all terms containing n to the left, all other terms to the right

-4n-15nn=6