-4-4(8-2x)=-40+7x

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Solution for -4-4(8-2x)=-40+7x equation: 



-4-4(8-2x)=-40+7x

We move all terms to the left:

-4-4(8-2x)-(-40+7x)=0

We add all the numbers together, and all the variables

-4(-2x+8)-(7x-40)-4=0

We multiply parentheses

8x-(7x-40)-32-4=0

We get rid of parentheses

8x-7x+40-32-4=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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