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-4.8x^2+1.6x+24=0
a = -4.8; b = 1.6; c = +24;
Δ = b2-4ac
Δ = 1.62-4·(-4.8)·24
Δ = 463.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{463.36}}{2*-4.8}=\frac{-1.6-\sqrt{463.36}}{-9.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{463.36}}{2*-4.8}=\frac{-1.6+\sqrt{463.36}}{-9.6} $
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