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-4.905x^2+12x+1=0
a = -4.905; b = 12; c = +1;
Δ = b2-4ac
Δ = 122-4·(-4.905)·1
Δ = 163.62
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-\sqrt{163.62}}{2*-4.905}=\frac{-12-\sqrt{163.62}}{-9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+\sqrt{163.62}}{2*-4.905}=\frac{-12+\sqrt{163.62}}{-9.81} $
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