-4.9t2+44.1t=0

Solution for -4.9t2+44.1t=0 equation:

-4.9t^2+44.1t=0

a = -4.9; b = 44.1; c = 0;
Δ = b2-4ac
Δ = 44.12-4·(-4.9)·0
Δ = 1944.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44.1)-\sqrt{1944.81}}{2*-4.9}=\frac{-44.1-\sqrt{1944.81}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44.1)+\sqrt{1944.81}}{2*-4.9}=\frac{-44.1+\sqrt{1944.81}}{-9.8}
$