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-4.9t^2+8.8t+10=
We move all terms to the left:
-4.9t^2+8.8t+10-()=0
We add all the numbers together, and all the variables
-4.9t^2+8.8t=0
a = -4.9; b = 8.8; c = 0;
Δ = b2-4ac
Δ = 8.82-4·(-4.9)·0
Δ = 77.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.8)-\sqrt{77.44}}{2*-4.9}=\frac{-8.8-\sqrt{77.44}}{-9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.8)+\sqrt{77.44}}{2*-4.9}=\frac{-8.8+\sqrt{77.44}}{-9.8} $
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