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-4.9x^2+13x-5=0
a = -4.9; b = 13; c = -5;
Δ = b2-4ac
Δ = 132-4·(-4.9)·(-5)
Δ = 71
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{71}}{2*-4.9}=\frac{-13-\sqrt{71}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{71}}{2*-4.9}=\frac{-13+\sqrt{71}}{-9.8} $
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