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-4/3x+4=1/2x-7
We move all terms to the left:
-4/3x+4-(1/2x-7)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x-7)!=0We get rid of parentheses
x∈R
-4/3x-1/2x+7+4=0
We calculate fractions
(-8x)/6x^2+(-3x)/6x^2+7+4=0
We add all the numbers together, and all the variables
(-8x)/6x^2+(-3x)/6x^2+11=0
We multiply all the terms by the denominator
(-8x)+(-3x)+11*6x^2=0
Wy multiply elements
66x^2+(-8x)+(-3x)=0
We get rid of parentheses
66x^2-8x-3x=0
We add all the numbers together, and all the variables
66x^2-11x=0
a = 66; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·66·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*66}=\frac{0}{132} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*66}=\frac{22}{132} =1/6 $
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