-4/5b=27

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Solution for -4/5b=27 equation: 



-4/5b=27

We move all terms to the left:

-4/5b-(27)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We multiply all the terms by the denominator


-27*5b-4=0

Wy multiply elements

-135b-4=0

We move all terms containing b to the left, all other terms to the right

-135b=4

b=4/-135

b=-4/135

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