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-4/5w-4/5=1/3w-7
We move all terms to the left:
-4/5w-4/5-(1/3w-7)=0
Domain of the equation: 5w!=0
w!=0/5
w!=0
w∈R
Domain of the equation: 3w-7)!=0We get rid of parentheses
w∈R
-4/5w-1/3w+7-4/5=0
We calculate fractions
(-180w^2)/375w^2+(-300w)/375w^2+(-125w)/375w^2+7=0
We multiply all the terms by the denominator
(-180w^2)+(-300w)+(-125w)+7*375w^2=0
Wy multiply elements
(-180w^2)+2625w^2+(-300w)+(-125w)=0
We get rid of parentheses
-180w^2+2625w^2-300w-125w=0
We add all the numbers together, and all the variables
2445w^2-425w=0
a = 2445; b = -425; c = 0;
Δ = b2-4ac
Δ = -4252-4·2445·0
Δ = 180625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{180625}=425$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-425}{2*2445}=\frac{0}{4890} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+425}{2*2445}=\frac{850}{4890} =85/489 $
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