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-4/5x+15x=-5
We move all terms to the left:
-4/5x+15x-(-5)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
15x-4/5x+5=0
We multiply all the terms by the denominator
15x*5x+5*5x-4=0
Wy multiply elements
75x^2+25x-4=0
a = 75; b = 25; c = -4;
Δ = b2-4ac
Δ = 252-4·75·(-4)
Δ = 1825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1825}=\sqrt{25*73}=\sqrt{25}*\sqrt{73}=5\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{73}}{2*75}=\frac{-25-5\sqrt{73}}{150} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{73}}{2*75}=\frac{-25+5\sqrt{73}}{150} $
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