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-4/5x+1=3x+1
We move all terms to the left:
-4/5x+1-(3x+1)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
-4/5x-3x-1+1=0
We multiply all the terms by the denominator
-3x*5x-1*5x+1*5x-4=0
Wy multiply elements
-15x^2-5x+5x-4=0
We add all the numbers together, and all the variables
-15x^2-4=0
a = -15; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-15)·(-4)
Δ = -240
Delta is less than zero, so there is no solution for the equation
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