-4/5x+2-x=48

Solution for -4/5x+2-x=48 equation:

-4/5x+2-x=48

We move all terms to the left:

-4/5x+2-x-(48)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

-1x-4/5x-46=0

We multiply all the terms by the denominator


-1x*5x-46*5x-4=0

Wy multiply elements

-5x^2-230x-4=0

a = -5; b = -230; c = -4;
Δ = b2-4ac
Δ = -2302-4·(-5)·(-4)
Δ = 52820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52820}=\sqrt{4*13205}=\sqrt{4}*\sqrt{13205}=2\sqrt{13205}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-230)-2\sqrt{13205}}{2*-5}=\frac{230-2\sqrt{13205}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-230)+2\sqrt{13205}}{2*-5}=\frac{230+2\sqrt{13205}}{-10}
$