-4/u+3=-(7/4u+12)+2

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Solution for -4/u+3=-(7/4u+12)+2 equation:


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

3-4/u = 2-((7/4)*u)-12 // - 2-((7/4)*u)-12

(7/4)*u-4/u-2+3+12 = 0

7/4*u^1-4*u^-1+13*u^0 = 0

(7/4*u^2+13*u^1-4*u^0)/(u^1) = 0 // * u^2

u^1*(7/4*u^2+13*u^1-4*u^0) = 0

u^1

(7/4)*u^2+13*u-4 = 0

(7/4)*u^2+13*u-4 = 0

DELTA = 13^2-(-4*4*(7/4))

DELTA = 197

DELTA > 0

u = (197^(1/2)-13)/(2*(7/4)) or u = (-197^(1/2)-13)/(2*(7/4))

u = 2/7*(197^(1/2)-13) or u = -2/7*(197^(1/2)+13)

u in { -2/7*(197^(1/2)+13), 2/7*(197^(1/2)-13)}

u in { -2/7*(197^(1/2)+13), 2/7*(197^(1/2)-13) }

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