-40+8r=3-(1-2r)

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Solution for -40+8r=3-(1-2r) equation: 



-40+8r=3-(1-2r)

We move all terms to the left:

-40+8r-(3-(1-2r))=0

We add all the numbers together, and all the variables

8r-(3-(-2r+1))-40=0



We calculate terms in parentheses: -(3-(-2r+1)), so:

3-(-2r+1)

determiningTheFunctionDomain
-(-2r+1)+3

We get rid of parentheses

2r-1+3

We add all the numbers together, and all the variables

2r+2

Back to the equation:

-(2r+2)



We get rid of parentheses

8r-2r-2-40=0

We add all the numbers together, and all the variables

6r-42=0

We move all terms containing r to the left, all other terms to the right

6r=42

r=42/6

r=7

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