-40/3z=40

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Solution for -40/3z=40 equation: 



-40/3z=40

We move all terms to the left:

-40/3z-(40)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We multiply all the terms by the denominator


-40*3z-40=0

Wy multiply elements

-120z-40=0

We move all terms containing z to the left, all other terms to the right

-120z=40

z=40/-120

z=-1/3

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